Crystal reports extract partial string
http://www.crystalreportsbook.com/forum/forum_posts.asp?TID=11764 WebJun 6, 2006 · If it's always Administrator the solution is much simpler, simply do an INSTR () for it and if > 0 show Administrator. As for the rightmost CN=, use INSTRREV. mid ( {table,field}, InstrRev ( {table,field}, "CN=")+3) This assumes that it's …
Crystal reports extract partial string
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WebMar 8, 2013 · I am using Crystal Reports XI R2. I am editing an existing report and need to add an alert if certain conditions are met. The report is a work order and some customers have given us specific instructions regarding a particular part they order from us. If the customer orders that part, I want an alert to print on the work order so the shop sees it. WebAug 7, 2012 · This date could appear anywhere within the string. At the moment I am relying on the fact that the date is placed at the end of the string, without a following fullstop, and using LEFT/RIGHT to extract each date part. These parts are then passed to another formula to create a full date:
http://www.crystalreportsbook.com/forum/forum_posts.asp?TID=9366 WebJul 14, 2024 · Filtering on part of a string. I'm a newbie to jet reporting although I have done some reporting using Crystal Reports and SSRS over the years. I need to filter based on the last 2 characters of a string. We flag something as obsolete by appending XX to the name or description. I want to create a Jet Report to list obsolete items.
WebNov 6, 2013 · Just an update. When I take just one record that has multiple (2)values the following formula, it works perfect. whileprintingrecords; stringvar array polyp_names:=split ( {RPTOBS.OBSVALUE},"-"); polyp_names [2] +chr (13)+polyp_names [4]; WebFormula : right ( {'FIELD'},instr (strreverse ( {'FIELD'}),"*")-1) Notes on the formula : {'FIELD'} represents the string field you are trying to extract specific data from. "*" represents the character in the field that indicates where you want to start. Function descriptions: right = Use this function to obtain just the right part of a string.
WebMar 7, 2011 · I need to be able to extract the date part of the string to a string variable and use this on a report. An example of two of the strings are '03-07-11 DAVISON COMPANY' and 'WORTH VILLAGE 03-03-11.' In example one, I want to extract '03-07-11' and in example two, I need to extract '03-03-11. I appreciate your help.
WebJun 13, 2012 · Topic: Extracting part of a string. Posted: 02 Jun 2016 at 3:30am. I have a text field that looks like this: Statement Processed, balance of 1156.00 for invoice 3000010004-0001Statement Path - SP After Ins, Step - 3 Self Pay After Ins 1. The … fitness xplodeWebNov 27, 2006 · 1973kk (Programmer) 22 Nov 06 14:11. The Val (str) function reads a string containing Numbers (example: an address, phone number, or social security number) and converts them to a decimal value. Val stops reading the string when it finds the first character in the string that it finds that it can not recognize as a number or as a space. fitness wylie txWebMay 24, 2024 · The file is dated 11/8/2000 so it might have been introduced with Crystal Reports V8. The function is called ExtractString (). It is designed to locate two character strings within a longer string and return all the characters in between those two strings. I have done something similar using the InStr () function but it is much more complicated. fitness xpress birminghamWebDec 13, 2016 · I am using Crystal Reports 13. I have field in my data that contains a string that includes various times. Examples: 0010800;0011000;0011200;0011400;0011600;0011800;0011900 … fitness yoga ballWebApr 9, 2014 · I am needing to extract part of a string. An example of the content of the string in my field is listed below. The field name is Command.Description. I need to extract what comes after the first" " and before the first "/" character. In this case i want the result … fitness yardWebSep 7, 2011 · Hi, Use this formula to extract everything to the left of " " : left (, Instr (, " ")-1); And, use this formula to extract everything to the right: Mid (, Instr (, " ")+1, length ()); You can even do this using an array: stringvar array a; a := split (, " "); a [1]; fitness xrWebFeb 28, 2024 · It's kinda hard to explain, but you're going to need to set up several variables, one for each part of the name. Then you will be searching the string to find your delimiter, in this case the space and get it's position in the string, which should be a number (x), … fitness yoga bodysuit factories